【CodeForces】A. I Wanna Be the Guy

Problem here

Problem

There is a game called “I Wanna Be the Guy”, consisting of n levels. Little X and his friend Little Y are addicted to the game. Each of them wants to pass the whole game. 
Little X can pass only p levels of the game. And Little Y can pass only q levels of the game. You are given the indices of levels Little X can pass and the indices of levels Little Y can pass. Will Little X and Little Y pass the whole game, if they cooperate each other?

Input

The first line contains a single integer n (1 ≤  n ≤ 100).

The next line contains an integer p (0 ≤ p ≤ n) at first, then follows p distinct integers a1, a2, …, ap (1 ≤ ai ≤ n). These integers denote the indices of levels Little X can pass. The next line contains the levels Little Y can pass in the same format. It’s assumed that levels are numbered from 1 to n.

Output

If they can pass all the levels, print “I become the guy.”. If it’s impossible, print “Oh, my keyboard!” (without the quotes).

Example

input

4 
3 1 2 3 
2 2 4

output

I become the guy.

input

4 
3 1 2 3 
2 2 3

output

Oh, my keyboard!

Note

In the first sample, Little X can pass levels [1 2 3], and Little Y can pass level [2 4], so they can pass all the levels both.

In the second sample, no one can pass level 4.

Solution

開一個布爾數組
每次讀入都將狀態改成true

#include <iostream>
#include <vector>
using namespace std;

int main(){
    int n;
    cin >> n;
    vector<bool> level;
    for(int i = 0; i < n; i++){
        level.push_back(false);
    }
    int x;
    cin >> x;
    while(x--){
        int tmp;
        cin >> tmp;
        level[tmp-1] = true;
    }
    int y;
    cin >> y;
    while(y--){
        int tmp;
        cin >> tmp;
        level[tmp-1] = true;
    }
    bool succ = true;
    for(int i = 0; i < level.size(); i++){
        if(level[i] == false){
            succ = false;
        }
    }

    if(succ){
        cout << "I become the guy." << endl;
    }else{
        cout << "Oh, my keyboard!" << endl;
    }
    return 0;
}